Imaginary Number Calculator

Compute powers of i, simplify expressions with imaginary numbers, and perform complex number arithmetic.

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Result

i7
-i

Step-by-Step Solution

i^7 = i^(4*1 + 3) = (i^4)^1 * i^3 = 1 * (-i) = -i

Understanding Imaginary Numbers

The imaginary unit i is defined as the square root of -1. Imaginary numbers extend the real number system to the complex number system, allowing solutions to equations like x² + 1 = 0. Every complex number can be written as a + bi, where a is the real part and b is the imaginary part.

Imaginary numbers were initially met with skepticism but are now fundamental to mathematics, physics, and engineering. They are essential in electrical engineering (AC circuits), quantum mechanics, signal processing, and control theory.

Powers of i — The Cycle

i1 = i

The imaginary unit itself. The square root of negative one.

i^1 = i

i2 = -1

By definition, i squared equals negative one.

i^2 = -1

i3 = -i

i cubed equals i squared times i, which is -1 times i.

i^3 = i^2 * i = -i

i4 = 1

The cycle completes. i to the fourth power equals one.

i^4 = (i^2)^2 = (-1)^2 = 1

Complex Number Arithmetic

Addition and Subtraction

To add or subtract complex numbers, combine the real parts and imaginary parts separately: (a + bi) + (c + di) = (a + c) + (b + d)i. This works just like combining like terms in algebra.

Multiplication

Multiply using FOIL (distributive property): (a + bi)(c + di) = ac + adi + bci + bdi² = (ac - bd) + (ad + bc)i. Remember that i² = -1.

Division

To divide complex numbers, multiply numerator and denominator by the conjugate of the denominator: (a + bi)/(c + di) = (a + bi)(c - di)/((c + di)(c - di)) = ((ac + bd) + (bc - ad)i)/(c² + d²).

Tips for Working with Imaginary Numbers

  • Powers of i repeat in a cycle of 4: i, -1, -i, 1, i, -1, -i, 1, ...
  • To simplify i^n, divide n by 4 and use the remainder to find the answer.
  • For negative exponents: i^(-n) = 1/i^n. Simplify i^n first, then take the reciprocal.
  • The conjugate of a + bi is a - bi. Multiplying a number by its conjugate gives a² + b² (always real).
  • sqrt(-n) = sqrt(n) * i for any positive number n.