Dihybrid Cross Punnett Square Calculator
Generate a 4x4 Punnett square for a dihybrid cross. Analyze genotype and phenotype ratios for two traits inherited simultaneously.
Trait Configuration
Parent 1
Parent 2
Cross Summary
4x4 Punnett Square
Genotype Ratios
Phenotype Ratios
Summary Statistics
What is a Dihybrid Cross?
A dihybrid cross is a genetic experiment that examines the inheritance of two different traits simultaneously. It tracks how alleles for two genes are passed from parents to offspring, revealing whether the traits are inherited independently (as predicted by Mendel's Law of Independent Assortment) or are linked.
In a dihybrid cross between two organisms that are heterozygous for both traits (AaBb x AaBb), the classic expected phenotype ratio in offspring is 9:3:3:1.
Understanding Genetics Terminology
Mendel's Laws
Law of Segregation
Each parent has two alleles for each gene, and they separate during gamete formation so each gamete contains only one allele for each gene.
Law of Independent Assortment
Alleles for different genes are distributed independently during gamete formation (assuming genes are on different chromosomes). This is why a dihybrid cross is possible.
How to Construct a Dihybrid Punnett Square
- Step 1: Identify the genotypes of both parents. Example: Parent 1 = AaBb, Parent 2 = AaBb.
- Step 2: Determine possible gametes for each parent. Parent 1: AB, Ab, aB, ab. Parent 2: AB, Ab, aB, ab.
- Step 3: Create a 4x4 grid with one parent's gametes across the top and the other down the side.
- Step 4: Fill in each cell by combining the row gamete with the column gamete.
- Step 5: Count and categorize the offspring genotypes and phenotypes.
The 9:3:3:1 Ratio
When crossing two double heterozygotes (AaBb x AaBb):
- 9/16 show both dominant traits (A_B_)
- 3/16 show dominant trait 1 and recessive trait 2 (A_bb)
- 3/16 show recessive trait 1 and dominant trait 2 (aaB_)
- 1/16 show both recessive traits (aabb)
This is the hallmark ratio of independent assortment.
Real-World Examples
Pea Plant Example (Mendel's Classic Experiment)
- Trait 1: Seed shape (R = round, r = wrinkled)
- Trait 2: Seed color (Y = yellow, y = green)
- Cross: RrYy x RrYy
- Expected: 9 round yellow : 3 round green : 3 wrinkled yellow : 1 wrinkled green
Dog Coat Example
- Trait 1: Coat color (B = black, b = brown)
- Trait 2: Coat length (S = short, s = long)
- Cross: BbSs x BbSs
- Expected: 9 black short : 3 black long : 3 brown short : 1 brown long
When the 9:3:3:1 Ratio Doesn't Apply
- Linked genes: Genes on the same chromosome may not assort independently.
- Incomplete dominance: Heterozygotes show an intermediate phenotype.
- Codominance: Both alleles are fully expressed.
- Epistasis: One gene affects the expression of another.
- Different parental genotypes: The 9:3:3:1 ratio only applies to AaBb x AaBb crosses.
Frequently Asked Questions
A: A cross examining the inheritance of two different traits simultaneously, typically shown using a 4x4 Punnett square.
A: For AaBb x AaBb, the phenotype ratio is 9:3:3:1.
A: Four types: AB, Ab, aB, and ab (each with equal probability of 25%).
A: A monohybrid cross examines one trait (2x2 Punnett square), while a dihybrid cross examines two traits (4x4 Punnett square).
A: Homozygous has identical alleles (AA or aa). Heterozygous has different alleles (Aa). If unknown, test crosses with recessive individuals can reveal the genotype.